PDA

View Full Version : Ship's Mast Head Height ............



Redwine
04-29-2004, 05:30 PM
It is needed to have the correct mast head height to be able to manage well manual shooting, mast head height represented in the graphics must to be in concordance with the theoretical values in the log book..........

Plus, will be great to have a system, like a grphic representation of the enemy ship, to have the height for all mast of the ships......

Some ships have many masts......... with a graphic representation we will be able to know all masts heights.......

This avoid to confuse mast head height data and let us to use any mast to calculations.........

Regards, Red.

______________________________
.
http://personales.ciudad.com.ar/pietraroja/imagenes/firmas/EscudoU552b.jpg
.
The Ancient History of the Submarine
"Subgenesis" (http://www.iespana.es/Subgenesis/subgenesis/sg00.htm)

Manual TDC
HTDC Tutorial (http://www.iespana.es/rotteufel/htdc_tutorial/a_start.htm)
.

Redwine
04-29-2004, 05:30 PM
It is needed to have the correct mast head height to be able to manage well manual shooting, mast head height represented in the graphics must to be in concordance with the theoretical values in the log book..........

Plus, will be great to have a system, like a grphic representation of the enemy ship, to have the height for all mast of the ships......

Some ships have many masts......... with a graphic representation we will be able to know all masts heights.......

This avoid to confuse mast head height data and let us to use any mast to calculations.........

Regards, Red.

______________________________
.
http://personales.ciudad.com.ar/pietraroja/imagenes/firmas/EscudoU552b.jpg
.
The Ancient History of the Submarine
"Subgenesis" (http://www.iespana.es/Subgenesis/subgenesis/sg00.htm)

Manual TDC
HTDC Tutorial (http://www.iespana.es/rotteufel/htdc_tutorial/a_start.htm)
.

Drebbel
04-30-2004, 10:32 AM
I think I remember WWII ship ID books only litsed the main (highest) mast for most vessels.


Drebbel

The Submarines of the Royal Netherlands Navy 1906 - 2004
http://www.DutchSubmarines.com/
We have a NEW FORUM:
http://www.dutchsubmarines.com/phpbb2/
http://www.dutchsubmarines.com/hosting/images/sig/drebbel/kmoorlwp.gif

Redwine
04-30-2004, 02:54 PM
Hi..... Drebbel.

I do not know real contact books from that age....

The matter is in SH2 we have a mast head height value, this is incorrect and plus.... we have no specification about which of all ship mast that size is corresponding for..........

A little trouble for manual shooting........

This contact books was made with information become from spies........

If you have a lateral picture of the ship silhouette, and you have one mast ...you have the rest............

I just noted, this may be implemented, just take a look at bottom of the web page of the mains official site of SH3........

At bottom there is a page of the contact book, with a lateral view of the enemy ship, with a height scale at side.........

http://www.silent-hunteriii.com/uk/home.php

Just at bottm of the page...........

This will help us to know any mast height for a determined ship...........

Regards, Red.

______________________________
.
http://personales.ciudad.com.ar/pietraroja/imagenes/firmas/EscudoU552b.jpg
.
The Ancient History of the Submarine
"Subgenesis" (http://www.iespana.es/Subgenesis/subgenesis/sg00.htm)

Manual TDC
"HTDC Tutorial" (http://www.iespana.es/rotteufel/htdc_tutorial/a_start.htm)
.

macker33
07-27-2004, 09:46 PM
Isnt it amazing what you can find down the back of things when you look,anyway i'm heading off on patrol again but want somebody to doublecheck my sums for me.

the formula i have for checking range is,and i'm not certain this is correct.

something 1 meter tall and 1 kilometer away looks 1 millimeter tall in the gunsite.(rough)

So a man would look 2mm tall and a ship 10m tall would look 1cm at 1km distance,

am i right to assume that the same ship 500m away would look 2cm tall?

Now the really tricky part,if you know something to be exactely 100m away and it only looks 1mm tall,how big is it really?(only joking i dont need to know that)

You are looking through your periscope or sight and have to think really quickly.Are the units on the periscope marked in millimeters?

anyway its a routine patrol and you spot the Iowa through your periscope,you check your ship i.d.book and see the iowa is 270m long even though it only looks 140mm in your periscope,

1,how far away is it?

2.if a torpedo travels at 45km per hour haw long will it take to reach the target?

3.if you are looking at the target for two minutes and in that time it travels 1mm how fast is it going?

4.if you fire a torpedo at the front tip of the boat where will it hit if it hits at all?

5.if a fletcher class destroyer is as far away as the target is how long will it take to reach you after the torpedo hits?

6.if 1km equels 5/8s of a mile then 1knot equels ?miles

I'm heading off on patrol again and dont know when i will return to port so theres something for somebody to think about,even though i'll be on patrol i will check for radio messages,so until then,fair weather and try not to get sunk.

Redwine
07-28-2004, 07:18 AM
@macker33

Dear Macker, I think so you need to start up learning the procedures needed from the initial steps..........

You need to apply some basic knows about trigonometry, not complex, not hard, so easy but you need to understand them........

Marks in the periscope do not indicates distances in milimiters, they indicates angles........

1,how far away is it?

Not posible to answer........
At first, you do not measure milimiters in the reticle you measure angles........
At second, you need to measure height, not longs, longs can be affected by relative target course, to use ship long angle you must to be sure to stay just at 90* at a side of the ship....... for that you need to use the angle from the floatation line to the top of the mast.......


2.if a torpedo travels at 45km per hour haw long will it take to reach the target?

You must to know the torpedo travel to the impact point in meters,.......... and then convert 45k/h to m/s, and then divide the travel in meters by the torpedo speed in m/s to obtain the impact time in seconds..........



3.if you are looking at the target for two minutes and in that time it travels 1mm how fast is it going?

Imposible to answer......... it depend on the target range, if it is near, it can be run a t 1 knot, if it is so far, it can be run at 100 knts.
To determine target speed, you must to measure ranges and angles and apply the Cosin Theoreme, obtain the target run during a determined time, and then dividing it by the time you will obtain the speed.................



4.if you fire a torpedo at the front tip of the boat where will it hit if it hits at all?

Sorry I can not to understand......... you are not the problem, I am the problem with my terrible bad english............



5.if a fletcher class destroyer is as far away as the target is how long will it take to reach you after the torpedo hits?

Imposible to answer too, it depend on many factors, torpedo travel to impact point, torpedo speed, the range from the Fletcher DD to your position, the max speed of the Fletcher Class, and if you stay quiet or you scape fast, away of the DD, or abeam of the DD........ it is not posible to answer it........


6.if 1km equels 5/8s of a mile then 1knot equels ?miles

1 Knot is 1 Nautical Mile at Hour............

10 Knots are 10 Nautical Miles in one Hour.....


One Nautical Mile is the long of the arc One Minute of Degree of the average earth circunference at ecuator at average sea level.......

One Degree is 60 Nautical Miles.


Best Regards, Red.

______________________________
.
http://personales.ciudad.com.ar/pietraroja/imagenes/firmas/EscudoU552b.jpg
.
The Ancient History of the Submarine
"Subgenesis" (http://www.iespana.es/Subgenesis/subgenesis/sg00.htm)

Manual TDC
"HTDC Tutorial" (http://www.iespana.es/rotteufel/htdc_tutorial/a_start.htm)
.

[This message was edited by Redwine on Wed July 28 2004 at 08:58 AM.]

TASKFORCE1x1
07-28-2004, 08:16 AM
Hi Redwine,

Maybe these recognition manuals will help.

Naval WWII Unclassified Recognition Manuals (http://www.history-on-cdrom.com/index.htm)

http://ubbxforums.ubi.com/images/smiley/16x16_smiley-very-happy.gif

Keep on Smiling'

macker33
07-28-2004, 02:14 PM
Emergency stop,i had to return to port quicker than i thought,

The imm in 2minutes is a rediculus number,i was off figureing out my own question it worked out something like 18hrs to travel 1km.
What i should have said was it traveled its own lenght in 2 minutes,how fast was it going?

As for the reticule being measured in millimeters,i didnt know things were done by angles.I'm pretty sure most opticle gun sights use millimeters and it was more a general question regarding rangefinding than submarine range finding in particular.
Its a good formula when you know how to work it out and is useful for more than just submarines.Using the formula of 1meter at 1km away looks 1mm you can figure everything out in a short time except of course angles.

1km = 1000 meters
1mile = 1609 meters
1 nautical mile =1852 meters.

10kmph =10000metersph
10mph =16090metersph
10 knots =18520metersph

The answers i have so far is,the iowa is approx 1900 meters away,the torpedo takes approx 2 minutes 36 seconds to hit the target.
The new speed answer is over 8kmph(i have to recheck it)

Its a handy sum to have and could be worth figuring out a quick formula.

(1 liter of water weights 1 kilogramme,you never know)

jeroen-79
07-28-2004, 04:25 PM
<BLOCKQUOTE class="ip-ubbcode-quote"><font size="-1">quote:</font><HR>Originally posted by macker33:
As for the reticule being measured in millimeters,i didnt know things were done by angles.I'm pretty sure most opticle gun sights use millimeters and it was more a general question regarding rangefinding than submarine range finding in particular.
Its a good formula when you know how to work it out and is useful for more than just submarines.Using the formula of 1meter at 1km away looks 1mm you can figure everything out in a short time except of course angles.<HR></BLOCKQUOTE>
A more correct way would be to state that a 1m object at a distance of 1km would take up the same angle as a 1mm object at 1m.
The point where the angle is measured is the observers eye.
<BLOCKQUOTE class="ip-ubbcode-quote"><font size="-1">quote:</font><HR>...[/quote

[quote]The answers i have so far is,the iowa is approx 1900 meters away,the torpedo takes approx 2 minutes 36 seconds to hit the target.
The new speed answer is over 8kmph(i have to recheck it)<HR></BLOCKQUOTE>To calculate the time a torpedo needs to reach the target you must not divide the distance between you and the target at the time the shot is fired but the distance the torpedo travels from the launch point to the point where the torpedo intercepts the target.
To get that distance you must calculate a firing solution.
If you shoot the torpedo straight at the ship it would be 338m away from it's initial position when the torpedo reaches that point.
For a stationary target the figures would be correct.
<BLOCKQUOTE class="ip-ubbcode-quote"><font size="-1">quote:</font><HR>Its a handy sum to have and could be worth figuring out a quick formula.<HR></BLOCKQUOTE>I'll type something after I get back from work tomorrow.
Off to bed now.

jeroen-79
07-29-2004, 11:49 AM
Okay, I'm back.

To calculate a firing solution you must know these variables:
The target's course: Ct
The target's speed: St
The tagret's bearing: Bt
The torpedo's speed: Sw

With this data the gyroangle (Cw) of the weapon will be:
Cw = arcsin( (sin(Bt-Ct-180) * St ) / Sw ) + Bt

To calculate the time the torpedo need sto reach the target you need:
The weapon's course: Cw (calculated above)
The target's bearing: Bt
The target's course: Ct
The target's distance: Dt
The weapon's speed: Sw

The time will be:
t = - (Dt * sin (Ct - Bt) ) / (Sw * sin(Ct - Cw)

To calculate how much distance the torpedo will travel you need:
The torpedo's speed: Vw
The time: t

Then the distance will be:
Dw = Vw * t

All variables must be with the same units.
(ie all distances in meters OR nautical miles but not both) and the results will be in the unoits that were put in. (ie if you put in kilometers/hour then time will be in hours)

macker33
07-31-2004, 08:35 PM
I,ve been thinking about this so much the last few days that i am starting to see numbers in my sleep,

I thought i could work distance out by making a table and then half and double the figures until i landed on the right solution,0m=1000mm,1000m=10mm,500m=500mm,2000m=5mm ,750m=250mm,etc.Now i am more confused than ever.
All the other sums(except target course)are pretty straight forward.

Thanks jeroen-79 for all the info,especially the"A more correct way would be to state that a 1m object at a distance of 1km would take up the same angle as a 1mm object at 1m"
The last 1m figure you quoted was the question to an answer i was chasing for a long while.I really really wanted to know how far from the eye the measuring divice had to be.That is just so useful.

Well i think i should just swallow my pride and admit temory defeat,i'll do what redwine suggested and learn events that way.

amazing fact.30knots = 55.5kmph approx which is 917meters per minute approx which is approximitely 15.28 meters per second.

macker33
08-01-2004, 08:08 PM
<BLOCKQUOTE class="ip-ubbcode-quote"><font size="-1">quote:</font><HR>Originally posted by Redwine:
Manual TDC
http://www.iespana.es/rotteufel/htdc_tutorial/a_start.htm
.

[This message was edited by Redwine on Wed July 28 2004 at 08:58 AM.]<HR></BLOCKQUOTE>

Well i visited the site but got distracted by the william brown stuff,i actually have a song about william brown in my record collection,if i had it on cd i would record it and try and get it to ya but i have it on a crackly 12 inch record.
if you have the money you can buy a record,cd or tape called"a sense of freedom"by the wolfe tones,its a good song,

If anybody can tell me wether a ship that appears half its size is 500m or 100m away i would be grateful.
If a ship you know to be 10m tall reaches the 45degree angle how close is it,if it reaches the 22.5degree angle how near is it,somebody should make a range table to simplify this stuff.

finchOU
08-01-2004, 09:05 PM
Lets see if my math skills have gone to ****...

SOH CAH TOA

USe Tangent....Oppisite over Adjacent

Tan (angle)= O/A A=distance from target (in meters)
O=mast height (in meters)

angle= 45 A=X (what we want) O=10

Tan 45= 10/x or X (Tan 45)= 10

(Tan 45=1......X=10) Therefore the Ship is only 10 meters away......

FULL REVERSE!!! http://ubbxforums.ubi.com/images/smiley/16x16_smiley-very-happy.gif

More realistic would be like 0.1 to 1 degree angel

lets try that

so we will say the angle is .5, the mast head hight still at 10

(Tan .5)=10/x

Tan .5= .00873(rounded)

x=10/.00873

x=1145 meters (rounded)

jeroen-79
08-03-2004, 10:46 AM
No need for tangentses.

As I said, a 1mm line 1m away takes up the same angle as a 1m mast 1km away.
The relationship between the two triangles is that they both have a 1:1000 opposite:adjacent ratio.

So we can say:
DR - distance reticle
HR - height reticle
DT - distance target
HT - height target

DR/HR = DT/HT
So:
HT*DR/HR = DT

In practice we can say:
DR - some constant
HR - apparent height of target in "marks"
DT - distance of target
HT - height of the target as read from a book

HT*DR/HR = DT

macker33
08-04-2004, 01:00 AM
I'm like a dog with a bone,can you believe i am still working this out,i'm getting close but it still aint got.
If i ever do figure out a good dead reckoner and if i get my scanner working i will post something up,along with an explanation in comic sans,i just hope yee can endure the suspense a bit longer.

macker33
08-04-2004, 01:16 AM
<BLOCKQUOTE class="ip-ubbcode-quote"><font size="-1">quote:</font><HR>Originally posted by jeroen-79:
No need for tangentses.

The relationship between the two triangles is that they both have a 1:1000 opposite:adjacent ratio.

DR - some constant

HT*DR/HR = DT<HR></BLOCKQUOTE>

DR - some constant,i am working with that,the constant being the ship height,ship length,

Its mainly on the basis that example:a 100meter ship 100meters away equels the width of the reticle marks then the same ship a quarter of the reticle mark should be (???)far away.
another example,a 127meter long ship 127meters away equels the width of the reticle marks,the constant being the ships length.

The dambusters in wwii used a different sight than normal,it was something like a coat hanger or a t-joint.this seems to be getting me somewhere.

I know yee know what yee are talking about but i gotta figure this table out so please excuse my thickness.I'm nearly there.

jeroen-79
08-04-2004, 10:49 AM
The dambustersight is a very good example of how you would use a reticle to get the range.
The dambuster sight however was made for a very specific situation and a very specific range.

How about a picture?
http://www.geocities.com/jeroen_huijben/reticle.txt

You can see two triangles, ABC' and ABC".
Both originate from A' (or A") and the ratio between AB and BC in both triangles is the same. (2:1)
ABC' is the reference reticle and ABC" is the real situation with a target with a specific height is at a specific distance.

A" is the periscope head from where the target is observed, B" is the target's waterline and C" is the target's masthead.
AB" and AC" are the lines of sight for the target's bottom and top.

B' is one mark on the reticle and C' is the next mark.

As you can see, AB" and AC" cross B' and C', so the target is exactly between two reticle marks.

You can see in the picture that the reticlemarks represent a height of 1 at a distance of 2.
We know that the distance:height ratio for these two marks is 2:1 and we know that the actual height of the target is 4.

Since the distance of a target that fills the two marks is always twice it's real height we can determine that it's distance is 8.

In this case, DR would be 2.
In other cases we would say that each unit on the reticle represents a height X that is a distance Y away.
Since it is easy to make each reticleunit represent 1 height unit we can say that DR = the distance Y.

So if 1 unit in the reticle represents 1m height at 145m distance then DR = 145.

Lastly, the length of the ship is not a good variable to use for calculating it's range since the apparent length of a ship is dependant on it's course.
Head on a ship will be very narrow while on it's side it will be very long.

The height is a better choice as it is not affected by the ship's course, from the perspective of a U-boat's periscope it only changes with distance.

macker33
08-04-2004, 10:12 PM
A pictures worth a thousand words,i'll be busy for the next few days so i've saved the page so i can study it later.I'm not far off cracking it completely and to my own satisfaction,this whole triangle thing is more useful than i thought.thanks again jeroen.

macker33
08-12-2004, 08:24 PM
Ok,just to possibly put some peoples minds to rest i have actually figured out the mast height and triangle thing.I thought i was being a genius until i figured out how simple it is.

Oh well whats next,navigating by the stars or estimating target course,the mind boggles.

macker33
08-21-2004, 05:32 PM
especially redwine,

ok redwine,i said i would try to get a song to you,just follow the link and click on a picture to download the tune behind the picture.

will brown (http://homepage.eircom.net/~macker33/admiralwilliambrown.htm)

enjoy and if the links dont work(anybody) be sure to let me know,

Redwine
08-23-2004, 08:39 AM
Thanks a lot Macker33.........

The history of the Admiral is for to make a film.....he was one of the most bave heart man in the history, and one of the fathers of my country.......

______________________________
.
http://personales.ciudad.com.ar/pietraroja/imagenes/firmas/EscudoU552b.jpg
.
The Ancient History of the Submarine
"Subgenesis" (http://www.iespana.es/Subgenesis/subgenesis/sg00.htm)

Manual TDC
"HTDC Tutorial" (http://www.iespana.es/rotteufel/htdc_tutorial/a_start.htm)
.

Redwine
08-23-2004, 08:54 AM
"mnemo technics" rules by Jeroen (triangle proporcionality) are so good, all rules you can found to simplify the calculation are wellcome.

I follow another way, just to take the mast head angle and apply the tg to obtain the range, all ways are valid, the most important is to understand it is posibly and easy.

Manual shooting gives lot of satisfaction........

Back to my original post...........

The fact in SH2 was.........

The value of the Mast Head height in the Contact Book are not correct.......... this make errors in calculations.......

Ship's Mast flickers constantly at long ranges, this make hard for you to take ranges.......

Ship's has many diferent masts, and the contact book do not show to wich one is corresponding the book vale.......... this last was solved in SH3 with a contact book with a lateral view and a height scale at side........very good for the team.

We need to wait for the sim to know wich level of manual shooting we will be able to perform...........

______________________________
.
http://personales.ciudad.com.ar/pietraroja/imagenes/firmas/EscudoU552b.jpg
.
The Ancient History of the Submarine
"Subgenesis" (http://www.iespana.es/Subgenesis/subgenesis/sg00.htm)

Manual TDC
"HTDC Tutorial" (http://www.iespana.es/rotteufel/htdc_tutorial/a_start.htm)
.

SailorSteve
08-23-2004, 10:17 PM
Redwine, I just read Drebbel's review at Subsim; it looks like there will be many realism options for the TDC:

1) Auto mode, which will be inaccurate enough to make it realistic.

2) Easy manual mode that actually has a tool to measure mast height.

3) Hardcore mode with proper scales and ships that don't flicker.

And several combinations in between, so everybody can be happy. It's looking better and better.

______________________________

The poster said "Join The Navy, See The World". So I did, and I'm here to tell you, the world is flat and blue.

Redwine
08-24-2004, 01:13 PM
We must to wait and take a look..........

Interesting the fact of the program will introduce some unaccuracy in Auto Mode.........

May be a random unaccuracy or failure ?

______________________________
.
http://personales.ciudad.com.ar/pietraroja/imagenes/firmas/EscudoU552b.jpg
.
The Ancient History of the Submarine
"Subgenesis" (http://www.iespana.es/Subgenesis/subgenesis/sg00.htm)

Manual TDC
"HTDC Tutorial" (http://www.iespana.es/rotteufel/htdc_tutorial/a_start.htm)
.

SailorSteve
08-24-2004, 04:34 PM
Redwine, have you watched the video yet? They have a great description of the TDC options, and it looks good.

______________________________

The poster said "Join The Navy, See The World". So I did, and I'm here to tell you, the world is flat and blue.

Redwine
08-24-2004, 08:21 PM
Nop......

What video ?

______________________________
.
http://personales.ciudad.com.ar/pietraroja/imagenes/firmas/EscudoU552b.jpg
.
The Ancient History of the Submarine
"Subgenesis" (http://www.iespana.es/Subgenesis/subgenesis/sg00.htm)

Manual TDC
"HTDC Tutorial" (http://www.iespana.es/rotteufel/htdc_tutorial/a_start.htm)
.

macker33
08-24-2004, 09:23 PM
<BLOCKQUOTE class="ip-ubbcode-quote"><font size="-1">quote:</font><HR>Originally posted by Redwine:

The history of the Admiral is for to make a film.<HR></BLOCKQUOTE>

Thats cool,can i be in the film?(not serious)

there was an article on the main irish news recently about the argintinian government wanting to give an irish mueseum a present of some anchors,but due to red tape and paperwork the anchors were in storage for 6 years waiting to get past customs.

Naturally enough the polititions were outraged that such a thing of significance could be held up in such a manner and how such a generous gesture by the argentinian government could be missed,there was an investigation ordered but eventually the anchors made it to mayo,true story.

SailorSteve
08-25-2004, 01:29 AM
<BLOCKQUOTE class="ip-ubbcode-quote"><font size="-1">quote:</font><HR>Originally posted by Redwine:
Nop......

What video ?<HR></BLOCKQUOTE>

This video! http://www.gamezone.tv/videos/silenthunter3.wmv

______________________________

The poster said "Join The Navy, See The World". So I did, and I'm here to tell you, the world is flat and blue.

Redwine
08-25-2004, 12:03 PM
Macker......

Sorry no info about the anchors, your comments are the first info I have about that.....

I cant believe that delay, is too much, but i think so is not due to stupid burocratics, may be some people are interesting in not send the historic pieces........

Will be a honour for us the pieces can be at the Mayo Town...........


Sailorsteve.........

Many thanks......

______________________________
.
http://personales.ciudad.com.ar/pietraroja/imagenes/firmas/EscudoU552b.jpg
.
The Ancient History of the Submarine
"Subgenesis" (http://www.iespana.es/Subgenesis/subgenesis/sg00.htm)

Manual TDC
"HTDC Tutorial" (http://www.iespana.es/rotteufel/htdc_tutorial/a_start.htm)
.

macker33
08-26-2004, 07:49 PM
Well thankfully the anchors have reached mayo now,theres big trouble for someone though.

HeibgesU999
08-26-2004, 09:57 PM
The Range is actually irrelevent in the equation provided angle on bow, speed, and course are correct.

The U.Kdt.Hdb stresses the importance of practicing range estimation. With the hot graphics hopefully we will be able to do this.

Redwine
08-27-2004, 06:38 AM
<BLOCKQUOTE class="ip-ubbcode-quote"><font size="-1">quote:</font><HR>Originally posted by macker33:
Well thankfully the anchors have reached mayo now,theres big trouble for someone though.<HR></BLOCKQUOTE>


Sorry my bad english Macker.........

Did the anchors arrived or not yet ?



Heibges.........

Thats correct........ to obtain AOB range is not relevant, it is needed to be inpueted into the TDC instrument later..........

______________________________
.
http://personales.ciudad.com.ar/pietraroja/imagenes/firmas/EscudoU552b.jpg
.
The Ancient History of the Submarine
"Subgenesis" (http://www.iespana.es/Subgenesis/subgenesis/sg00.htm)

Manual TDC
"HTDC Tutorial" (http://www.iespana.es/rotteufel/htdc_tutorial/a_start.htm)
.

macker33
08-30-2004, 08:35 AM
<BLOCKQUOTE class="ip-ubbcode-quote"><font size="-1">quote:</font><HR>Originally posted by Redwine:
Did the anchors arrived or not yet ?
<HR></BLOCKQUOTE>

Yep,for the people in mayo its a really big deal,i know a few people in galway so if i am up that direction i might drop up to mayo to check the mueseum out.


<BLOCKQUOTE class="ip-ubbcode-quote"><font size="-1">quote:</font><HR>Originally posted by heibgesu999:
The Range is actually irrelevent in the equation provided angle on bow
<HR></BLOCKQUOTE>

You might know something i dont but dont you need to know how far the target is away from you so you can tell how long the torp has to travel to hit the target?

jeroen-79
08-30-2004, 10:45 AM
The target's range is not relevant for determining the gyroangle if you assume the torpedo to start from under the periscope and immediately turn on it's course.

If you want to consider that the torpedo starts forward of the periscope and doesn't immediately turn on the right course then the target's range would matter.
It would matter most at short ranges, for target's on the ship's sides and for fast targets.
At long ranges the offset between periscope and tubes can be neglected.

Since most torpedoes don't have an unlimited supply of fuel you need the target's range to determine how long the torpedo must travel to the interceptpoint and determine if the torpedo can reach it.
But at short ranges and slow targets you may assume that the torpedo is within range.

macker33
08-30-2004, 01:41 PM
You have to know how long it will take to reach the target because the target will have moved during the time the torp is launched and the time the torp reaches the range of the target.Simple deflection shooting.